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develop.py
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54 lines (44 loc) · 1.4 KB
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"""
This is a script to continuously re-run 'manage.py runserver' even
when it throws an exception.
Ordinarily this wouldn't really be needed, but because our app is running
in Docker, we don't want to have to restart a bunch of containers
just because there's a syntax error in one of our files.
"""
import os
import sys
import signal
import subprocess
import time
ROOT_DIR = os.path.abspath(os.path.dirname(__file__))
path = lambda *x: os.path.join(ROOT_DIR, *x)
def run_server():
return subprocess.Popen([
sys.executable,
path('manage.py'),
'runserver',
'--host', '0.0.0.0'
])
def write(message):
sys.stdout.write(message + '\n')
sys.stdout.flush()
server = None
sigterm_received = False
def handle_sigterm(signum, frame):
global server
global sigterm_received
print "SIGTERM received."
sigterm_received = True
if server is not None: server.send_signal(signal.SIGTERM)
if __name__ == '__main__':
signal.signal(signal.SIGTERM, handle_sigterm)
while True:
server = run_server()
retval = server.wait()
write("Development server exited with code %d. " % retval)
if sigterm_received: break
for i in [3, 2]:
write("Restarting development server in %d seconds... " % i)
time.sleep(1)
write("Restarting development server in 1 second... ")
time.sleep(1)