0577-employee-bonus.sql

-- 577. Employee Bonus
-- Easy
-- https://leetcode.com/problems/employee-bonus

/*
Table: Employee
+-------------+---------+
| Column Name | Type    |
+-------------+---------+
| empId       | int     |
| name        | varchar |
| supervisor  | int     |
| salary      | int     |
+-------------+---------+
empId is the primary key column for this table.
Each row of this table indicates the name and the ID of an employee in addition to their salary and the id of their manager.

Table: Bonus
+-------------+------+
| Column Name | Type |
+-------------+------+
| empId       | int  |
| bonus       | int  |
+-------------+------+
empId is the primary key column for this table.
empId is a foreign key to empId from the Employee table.
Each row of this table contains the id of an employee and their respective bonus.

Write an SQL query to report the name and bonus amount of each employee with a bonus less than 1000.
Return the result table in any order.
The query result format is in the following example.

Example 1:
Input:
Employee table:
+-------+--------+------------+--------+
| empId | name   | supervisor | salary |
+-------+--------+------------+--------+
| 3     | Brad   | null       | 4000   |
| 1     | John   | 3          | 1000   |
| 2     | Dan    | 3          | 2000   |
| 4     | Thomas | 3          | 4000   |
+-------+--------+------------+--------+
Bonus table:
+-------+-------+
| empId | bonus |
+-------+-------+
| 2     | 500   |
| 4     | 2000  |
+-------+-------+
Output:
+------+-------+
| name | bonus |
+------+-------+
| Brad | null  |
| John | null  |
| Dan  | 500   |
+------+-------+
*/

SELECT
  Employee.name, Bonus.bonus
FROM
  Employee
LEFT JOIN Bonus ON Employee.empId = Bonus.empId
WHERE
  Bonus.bonus < 1000 OR
  Bonus.bonus IS NULL
;