Modified Solution for week-2-js easy problems

week-2/week-2-js/easy/anagram.js

@@ -5,7 +5,13 @@
 */
 
 function isAnagram(str1, str2) {
-
+if(str1.length !== str2.length){
+  return false;
+}
+function sortingStr(str){
+  return str.toLowerCase().split('').sort().join('');
+}
+return sortingStr(str1) === sortingStr(str2);
 }
 
 module.exports = isAnagram;

week-2/week-2-js/easy/expenditure-analysis.js

@@ -4,17 +4,31 @@
   transactions is an array where each
   Transaction - an object like 
         {
-		id: 1,
-		timestamp: 1656076800000,
-		price: 10,
-		category: 'Food',
-		itemName: 'Pizza',
-	}
+    id: 1,
+    timestamp: 1656076800000,
+    price: 10,
+    category: 'Food',
+    itemName: 'Pizza',
+  }
   Output - [{ category: 'Food', totalSpent: 10 }] // Can have multiple categories, only one example is mentioned here
 */
 
 function calculateTotalSpentByCategory(transactions) {
-  return [];
+  const totals = {};
+  for (let transaction of transactions) {
+    const { category, price } = transaction;
+    if (totals[category]) {
+      totals[category] += price;
+    }
+    else {
+      totals[category] = price;
+    }
+  }
+  const result = [];
+  for (let category in totals) {
+    result.push({ category, totalSpent: totals[category] });
+  }
+  return result;
 }
 
 module.exports = calculateTotalSpentByCategory;

week-2/week-2-js/easy/findLargestElement.js

@@ -1,12 +1,18 @@
 /*
-  Write a function `findLargestElement` that takes an array of numbers and returns the largest element.
-  Example:
-  - Input: [3, 7, 2, 9, 1]
-  - Output: 9
+  Write a function `findLargestElement` that takes an array of numbers and returns the largest element.
+  Example:
+  - Input: [3, 7, 2, 9, 1]
+  - Output: 9
 */
 
 function findLargestElement(numbers) {
-
+    let max = numbers[0];
+    for (let i = 0; i < numbers.length; i++) {
+        if (numbers[i] > max) {
+            max = numbers[i];
+        }
+    }
+    return max;
 }
 
 module.exports = findLargestElement;